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q2p2 0,90 90% ?q0p0 ?q1p1 Проверка Ip Iq=IQ 1,09*1,79 = 1,96 Ip Iq=IQ 1,06*0,85 = 0,90 В феврале за счет увеличения физического объема товарооборота на 79% и за счет увеличения цены на 9%, товарооборот возрос на 96% (по сравнению с январем) В марте за счет.
www.refbank.ru/stat/12/stat12.html
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P0 and (P0 , Q1 ) ∈ B . b b b b The interesting bit is working out whether the processes are weakly bisimilar, and nding the observation relation. The proof that it really is an observation bisimulation is pretty tedious.
www.doc.ic.ac.uk/~pg/Concurrency/Exercises/CCS/ans5.pdf
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xi j2 ^ (4) i=1 2 over P 2 P(Q). To develop theoretical and computational results for this problem, it is necessary to have a topology on P(Q), continuity of the function P !
(P ) N (P ), P 2 N (P ). By construction P 2 P0 (Q), so P0 (Q) is dense in P(Q) relative to .
www.ncsu.edu/crsc/reports/ftp/pdf/crsc-tr99-40.pdf
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Результаты поиска по запросу: P?P>P8Q P:P>P2P0Q Q P8Q Q P5P.
ratupsphisrie.ueuo.com/p/362/poisk.html
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включил логирование вот что выдает: Ошибка: 502 Proxy Error ( P#P:P0P7P0P=P=Q P9 SSL-P?P>QQ P=P5 QP0P7QP5Q P5P=.
SSL-P7P0P?QP>Q P>P2. ) (EIdHttpProxyError).
www.litemanager.ru/forum/ru/viewtopic.php?p=3100&sid=c1b0050ccc6f3da6525dc97dca919aad
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Q; - Полная активная и реактивная мощность на частотах гармоник, S(n); P(n); Q(n); - Активная и реактивная мощность обратной и нулевой последовательности P2; P0; Q2; Q0; - Активная энергия WPT с учетом искажений; - Реактивная энергия WQ. РД 153-34.0-15.502-2002.
www.tke.ru/node/326
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5 of [50], and Refs. therein): I4 (Γ) = − pΛ qΛ 2 +4 i<j pi qi pj qj − 4p0 q1 q2 q3 + 4q0 p1 p2 p3 = −Det (Ψ) , (8) where Det (Ψ) is the so-called Cayley’s hyperdeterminant [3]. In the next three Sections we will discuss the explicit solutions of. the equations of motion of the scalars s, t and u in the dyonic background of an extremal BH of the stu model, also named Attractor Flow Equations.
www.mdpi.com/1099-4300/10/4/507/pdf
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f0(x D f2(x, D f1(x Parallel De Automaton M jest decomposable into two sub-automata M1, M2 working in parallel iff in the set of states S of this automaton there exist two non-trivial partitions p1, p2 with substitution property such that p1 · p2 = p(0) Q Q q D.
web.cecs.pdx.edu/~mperkows/CLASS_573/MARCH_3_06/LECTURE_C_1_Intro_FSM_Decomposition.ppt
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Hence, by the Routh-Hurwitz theorem, when τ 0, the positive equilibrium E∗ of system 1.6 is locally asymptotically stable. If iω ω > 0 is a root of 3.11 , separating the real and imaginary parts, we obtain p 0 − p2 ω 2 −ω 3 p1 ω q2 ω2 cos ωτ − q1 ω sin ωτ − q0 cos ωτ, −q2 ω2 sin ωτ − q1 ω cos ωτ q0 sin ωτ.
downloads.hindawi.com/journals/ddns/2009/285934.pdf
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We introduce two vectors p and λ for the PageRank and leakage of the boosting pages, q0λ p1 p 0 1 p2 λ2 . p= λ= . ... . pk λk With this the q matrix of the qm p1 notation, p2 pk q2 equation 1 PageRank scores of the spam farm pages can be written as p0.
www.vldb2005.org/program/paper/thu/p517-gyongyi.pdf
